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How does the SML MLton compiler deal with type ranges and cases of Coercion? More specifically, I am wondering if: It guarantees that it will never call a function which is passed an argument with a type that is out of the function's range. It treats cases of Coercion differently (ie. always coerces the argument to the type of the function) than situations where a direct call is needed. For example, the following code would be acceptable: fun foo(str : str) = () foo("abc") (* should never execute *) fun bar() = 100 So, how does the compiler know that, given foo, str will be coercible to str? And given bar, will the compiler always return 100? A: No, it's not guaranteed. The Coercion monad gives the semantics of how something might be coerced. In the absence of the monad, it's not obvious what the semantics for coercion are. As an example, suppose we have a function with the type like so: fun test t = case t of Int => 42 | String => "test" Is t an integer or a string? 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A number of onshore power generating stations are now being readied for construction and supply to cater for the high electricity demand of a proposed container port at Stapylton on Cape Moreton Island. 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